`dataFrame.column.compare — lte()`

Description

The lte() method of the compare object returns a boolean mask indicating which values are lower than or equal to the specified number.

Signature

dataFrame.column(columnName).compare.lte(number)

Scope: column
Family: compare
Returns: mask

Arguments

columnName (string): The name of the column to compare values from.
number (number): The value to compare against.

Returns

mask ( boolean[] )

A boolean mask indicating the rows whose values are lower than or equal to the specified number.

Lower than or equal to the number: 1
Otherwise: 0

Example

// higlight rows where the column 'revenue' contains a value lower than or equal to 2000
var mask = df.column('revenue').compare.lte(2000);

// set mask to dataFrame
df.column('lte_2k').set(mask)